Finite dimension of vector spaces #
Definition of the rank of a module, or dimension of a vector space, as a natural number.
Main definitions #
Defined is FiniteDimensional.finrank
, the dimension of a finite dimensional space, returning a
Nat
, as opposed to Module.rank
, which returns a Cardinal
. When the space has infinite
dimension, its finrank
is by convention set to 0
.
The definition of finrank
does not assume a FiniteDimensional
instance, but lemmas might.
Import LinearAlgebra.FiniteDimensional
to get access to these additional lemmas.
Formulas for the dimension are given for linear equivs, in LinearEquiv.finrank_eq
.
Implementation notes #
Most results are deduced from the corresponding results for the general dimension (as a cardinal),
in Dimension.lean
. Not all results have been ported yet.
You should not assume that there has been any effort to state lemmas as generally as possible.
The rank of a module as a natural number.
Defined by convention to be 0
if the space has infinite rank.
For a vector space V
over a field K
, this is the same as the finite dimension
of V
over K
.
Equations
- FiniteDimensional.finrank R V = Cardinal.toNat (Module.rank R V)
Instances For
This is like rank_eq_one_iff_finrank_eq_one
but works for 2
, 3
, 4
, ...
A finite dimensional space is nontrivial if it has positive finrank
.
A finite dimensional space is nontrivial if it has finrank
equal to the successor of a
natural number.
A (finite dimensional) space that is a subsingleton has zero finrank
.
If a vector space (or module) has a finite basis, then its dimension (or rank) is equal to the cardinality of the basis.
If a vector space (or module) has a finite basis, then its dimension (or rank) is equal to the
cardinality of the basis. This lemma uses a Finset
instead of indexed types.
A ring satisfying StrongRankCondition
(such as a DivisionRing
) is one-dimensional as a
module over itself.
The vector space of functions on a Fintype ι
has finrank equal to the cardinality of ι
.
The vector space of functions on Fin n
has finrank equal to n
.
The dimension of a finite dimensional space is preserved under linear equivalence.
Pushforwards of finite-dimensional submodules along a LinearEquiv
have the same finrank.
The dimensions of the domain and range of an injective linear map are equal.
The rank of a set of vectors as a natural number.
Equations
- Set.finrank K s = FiniteDimensional.finrank K ↥(Submodule.span K s)
Instances For
Given a family of n
linearly independent vectors in a finite-dimensional space of
dimension > n
, one may extend the family by another vector while retaining linear independence.
Given a family of n
linearly independent vectors in a finite-dimensional space of
dimension > n
, one may extend the family by another vector while retaining linear independence.
Given a nonzero vector in a finite-dimensional space of dimension > 1
, one may find another
vector linearly independent of the first one.
A finite family of vectors is linearly independent if and only if its cardinality equals the dimension of its span.
A family of finrank K V
vectors forms a basis if they span the whole space.
Equations
- basisOfTopLeSpanOfCardEqFinrank b le_span card_eq = Basis.mk (_ : LinearIndependent K b) le_span
Instances For
A finset of finrank K V
vectors forms a basis if they span the whole space.
Equations
- One or more equations did not get rendered due to their size.
Instances For
A set of finrank K V
vectors forms a basis if they span the whole space.
Equations
- One or more equations did not get rendered due to their size.
Instances For
If there is a nonzero vector and every other vector is a multiple of it, then the module has dimension one.
If every vector is a multiple of some v : V
, then V
has dimension at most one.